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1 D A particle P is projected from a point A with speed u m s–1 at an angle of elevation , where cos = 5 4. The point B, on horizontal ground, is vertically below A and AB = 45 m. After projection, P moves freely under gravity passing through point C, 30 m above the ground, before striking the ground at the point D, as shown in Figure 3.

10. A car travels with a uniform velocity of 20 m-1.The driver applies the brakes and the car comes to rest in 10 second. Calculate the retardation. (S) (a = - 2 ms-2) 11. A ball is thrown vertically upwards, At highest point of its path what will be its instantaneous velocity & acceleration. (U) 12.

A ball is thrown vertically upward with a speed of 25.0 m/s. (a) How high does it rise? (b) How long does it take to reach its highest point? (c) How long does it take to hit the ground after it ...

The ball rises to a height of 3.3 m above the ground, or 3.3 m above the y = 0 position. You also have information about velocity at this point. You know that gravity causes an object to slow down as it moves upward and speed up as it moves downward.

A ball is thrown vertically upward with a speed of 25.0m/s. (a) How high does it rise? (b) How long does it take to reach its highest point? (c) How long does the ball take to hit the ground after it reaches its highest point? (d) What is its velocity when it returns to the level from which it started? Solution . Problem 23.

500 kg ms 1, so final momentum of 80 kg skater — 540 kg ms 1. Final velocity = 540/80 = 6.75 ms Two skaters are skating together at a steady velocity of 8 m s-1. Their masses are 80 kg and 50 kg. The lighter skater is pushed forwards and accelerates to 10 ms-I. Calculate the new speed of her partner. (10 min)

A ball is thrown upwards from the ground with an initial speed of u. The ball is at a height of 80 m at two times. The time interval being 6 sec. Find u.

1) When a ball is thrown up and it comes down When the ball leaves the hand, there is no upward force acting on the ball. The only force acting on the ball is its weight. This net force is opposite to the motion of the ball, hence causing the ball to decelerates. Refer to this post for the explanation (comics)

1. An object is projected vertically upwards at time t = 0. Air resistance is negligible. The object passes the same point above its ... A ball of mass m is thrown with an initial speed of u at an angle θ to the horizontal as shown. Q is the highest point of the motion. ... of 16 ms and leaves the container at a speed of 20 m s .

The point on the top of the wheel has a speed (relative to the ground) that is twice the velocity of the center of mass. Consider the point in contact with the ground: R v v v cm rel cm cm Þ Þ Þ vrel cm = −R w vcm = R w vgnd = −R w + R w = 0 The point in contact with the ground has a speed of zero, i.e. momentarily at rest.

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A small metal ball is thrown vertically upwards with an initial speed of 2 0 ms-1. Assuming that air resistance is negligible, calculate : i) the time taken by the ball to reach its highest point : ii) the maximum height reached : iii) the height, h 1.5 of the ball 1. 5 s after it was thrown : iv) the speed, v 4 of the ball 4 s after it was thrown.

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A ball is thrown with a speed of 8 ms–1 at an angle of 30° to the horizontal. How high above its point of projection is it when it has travelled 2 m horizontally? Solution The time for the ball to travel 2 m horizontally is given by equation (7), x =Utcosθ, as t = x U cosθ, Here x =2, U =8, θ=30, so that t = 2 8cos30 =0.29s Taking g =10 ...

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Oct 05, 2011 · A ball is thrown vertically upwards at 25ms^-1. Find the length of time for which the ball is above 3m from the point of projection. STEP ONE s=3m u=25 v=? a=-9.8ms^-2 t=?

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3.) A ball is thrown vertically upward, what are the velocity and acceleration at the peak where it reaches its maximum altitude. 4.) A ball is thrown down with an initial speed of 10 m/s. A second ball is dropped from rest at the same height as the first ball. (a) compare the acceleration of each ball while they are in motion.

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CHAPTER 1 4 Example 2 A ball is thrown horizontally, with speed 20 m s 1, from the top of a building which is 30 m high. Find a the time the ball takes to reach the ground, b the distance between the bottom of the building and the point where the ball strikes the ground. Resolving the velocity of projection horizontally and vertically R(→) u ...

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A ball is thrown vertically upward with a speed of 25.0m/s. (a) How high does it rise? (b) How long does it take to reach its highest point? (c) How long does the ball take to hit the ground after it reaches its highest point? (d) What is its velocity when it returns to the level from which it started? Solution:

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atmosphere) are given by U= 8 P−5 P 6 metre and T= 6 P metre, where P is in second. The velocity with which the projectile is projected, is ?1)14 ?ms 5 2)10 ms ? 5 3)8 ms 5 11. A body is thrown vertically up with a velocity Q.It passes three points #, $ and % in its upward journey with velocities è 6, è 7 and è 8 respectively.

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The launcher is placed on the ground and a ball is fired vertically upwards. The vertical speed of the ball as it leaves the top of the launcher is 7-0 ms . The effects of air resistance can be ignored. (a) (i) (ii) ball O top of launcher launcher Calculate the maximum height above the top of the launcher reached by the ball.

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Aug 18, 2008 · When an object is thrown upward, it decelerates 9.8 m/s each second, until its velocity = 0 m/s. At this time the object is at its highest point. Then it accelerates downward at 9.8 m/s each...

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